Movements of Kimi are shown in the given figure.
Clearly, final position is T which is in the north of her house.
Show the figure,
Starting from the point A and passing through the points B, C and D, Deepak reaches the point E. Hence, he is in North direction from his house.
Let point A is the starting point I.e., school of Shyam
Point D is the ending point,
From, figure, AB = CD = 5 km
And AD = BC = 10 km
So, Shyam is 10 km far away from his school and in West direction from school.
The pointer which was showing last started showing South.
After accident, E – S and S – W
W – N and N – E
So, Pointer turned 90 degree clockwise.
Let A and B started from point O. A towards West and B towards East and at last they reached N and Q. Respectively,
ON = √[(NM)2+ (MO)2]
ON = √(42+ 32)
ON = 5 km
OQ = √[(NQ)2+ (NO)2]
OQ = √(32+ 42)
OQ = 5 km
Let the man starts from the point A and passing through,
B and C, he reaches D. Clearly, he is now facing North.
Figure is drawn as,
Now, to go back home Ram has to cycle = ( ED + DA ) = (15 + 6) = 21 km
Now, distance Ravi to cycle to reach home is (ED + DA) = (10 + 5) = 15 km
Distance between the starting point and end point is AD.
Now, AD2 = AE2 + DE2
AD2 = 62 + 82
So, AD = √(36+64)
AD = √100 = 10 km
The movement of man is shown in the figure below
From figure, finally, he is facing in the OS direction, which is South West.
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