Zcos
Score Card
Quantitative Aptitude
Total Ques
Attempt
Correct
Score
Easy
24 Ques
0
0
24
Medium
196 Ques
0
2
194
Hard
30 Ques
0
0
30
General Instruction:
Test contains total 20 questions.
Time allowed to finish is 30 mins.
There is no negative marking.
Question - 1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
120 metres
180 metres
324 metres
150 metres
Solution:
Length of train is X.
Crossing time = length of train/speed of train
9 = X/(60 x 5/18)
X = 9 x 60 x 5/18
X = 150 metres
Question - 2.
1268 ÷ 8 ÷ 2 = ?
17.75
65.52
74.32
79.25
Solution:
1268 ÷ 8 = 158.25
158.25 ÷ 2 = 79.25
Question - 3.
15.5% of 850 + 24.8% of 650 = ?
293
330
325
280
Solution:
15.5% of 850 + 24.8% of 650 = ?
(15.5/100) x 850 + (24.8/100) x 650
(13175 + 16120)/100 = 293
Question - 4.
What amount would a receive on a principal of Rs. 4,000 after two years on simple interest @ 5 p.c.p.a.
Rs. 4,161
Rs. 5,200
Rs. 4,400
Rs. 2,400
Solution:
Amount = S.I. + Principal
S.I. = (Principal x rate of interest x time)/100
S.I. = (4000 x 5 x 2)/100 = 400
Then, Amount = S.I. + Principal
Amount = 400 + 4000 = 4400
Question - 5.
Find the missing number ?
9 62 ? 1854 7415 22244
433
309
406
371
Solution:
9 62 ? 1854 7415 22244
(9 x 7) -1 = 62
(62 x 6) - 1 = 371
(371 x 5) - 1 = 1854
Question - 6.
Two pipes A and B can fill a cistern in 37(1/2) minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:
5 min
9 min
12 min
15 min
Solution:
Let B be turned off after x minutes. Then,
Part filled by (A + B) in X min. + Part filled by A in (30 - X) min. = 1.
X(2/75 + 1/45) + (30 - X)(2/75) = 1
11X/225 + (60 - 2X)/75 = 1
11X + 180 - 6X = 225
X = 9 min
Question - 7.
A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is:
10%
18%
24%
28%
Solution:
Let original length = X and original breadth = Y.
Decrease in Area = XY - [(80/100)X x (90/100)Y]
Decrease in Area = [XY - (18/25)XY] = 7/25XY
Decrease % = [(7/25)XY x (1/XY)100]% = 28%
Question - 8.
By how much is 3/4 of 968 less than 7/8 of 1008 ?
154
146
165
156
Solution:
(7/8)1008 - (3/4)968
(7 x 126) - (3 x 242)
882 - 726 = 156
Question - 9.
Two third of three fourth of one fifth of a number is 15. What is 30 percent of this number ?
45
60
75
30
Solution:
(2/3) x (3/4) x (1/5) x X = 15
X = 150
Then 30% of X = (30/100)150 = 45
Question - 10.
A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
10
20
21
25
Solution:
Suppose the can initially contains 7X and 5X of mixtures A and B respectively.
Quantity of A in mixture left = [7X - (7/12)x9] litres = [7X - (21/4)] litres
Quantity of B in mixture left = [5X - (5/12)x9] litres = [5X - (15/4)] litres
[7X - (21/4)]/[{5X - (15/4)} + 9] = 7/9
(28X - 21)/(20X + 21) = 7/9
252X - 189 = 140X + 147
112X = 336
X = 3
So, the can contained 21 litres of A.
Question - 11.
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
1/3
3/4
7/19
9/21
Solution:
Total number of balls = (8 + 7 + 6) = 21.
Let E = event that the ball drawn is neither red nor green
E = event that the ball drawn is blue.
n(E) = 7.
P(E) = n(E)/n(S) = 7/21 = 1/3
Question - 12.
The ratio of the present ages of Anju and Sandhya is 13:17. Four years ago the ratio of their ages was 11:15. What will be the ratio of their ages six years hence ?
3 : 4
7 : 8
4 : 5
6 : 5
Solution:
Let Present age of Anju = 13X
Present age of Sandhya = 17X
(13X - 4)/(17X - 4) = 11/15
195X - 60 = 187X - 44
8X = 16
X = 2
Present age of Anju = 26
Present age of Sandhya = 34
Age ratio of 6 years hence = (26 + 6) : (34 + 6)
Age ratio of 6 years hence = 32 : 40
Age ratio of 6 years hence = 4 : 5
Question - 13.
What would be the compound interest accrued on an amount of Rs 8000 at the rate of 15 p.c.p.a. in three years?
Rs. 4283
Rs. 4051
Rs. 4167
Rs. 4325
Solution:
Amount = 8000[1 + (15/100)]
Amount = 8000[(20 + 3)/100]
Amount = 8000 x (23/20) x (23/20) x (23/20)
Amount = 23 x 23 x 23 = 12167
C.I. = Rs. 12167 - 8000 = Rs. 4167
Question - 14.
The ratio of the present ages of mother and daughter is 7 : 1. Four years ago the ratio of their ages was 19 : 1. What will be the mother's age four years from now ?
42 years
38 years
46 years
36 years
Solution:
Let the present age of mother and daughter be 7X and X.
Then, (7X - 4)/(X - 4) = 19/1
7X - 4 = 19X - 76
12X = 72
X = 6
Mother's age 4 years hence = (7 x 6) + 4 = 46 years
Question - 15.
√(360 - 225 x 2 + 346) = ?
16
17
18
15
Solution:
√(360-225 x 2+346)
√(706 - 450)
√256 = 16
Question - 16.
Perimeter of a square is equal to the perimeter of a rectangle of length 8 cm and breath 7 cm. What is the circumference of a semicircle whose diameter is equal to the side of square? (Rounded off to two decimal place)
38.57 cm
48.26 cm
39.24 cm
40.35 cm
Solution:
Perimeter of square = perimeter of ractangle
4 a = 2 (L + B)
4 a = 2(8 + 7)
4a = 30
a = 7.5
Radius of circle (R) = 7.5
Circumference of Semicircle = Π x R + 2R
Circumference of Semicircle = 7.5 x 22/7 + (2 x 7.5)
Circumference of Semicircle = 23.57 + 15 = 38.57
Question - 17.
When 30% of one number is subtracted from another number , the second number reduces to its four-fifth. What is the ratio of the first to the second number ?
4 : 7
3 : 2
2 : 5
2 : 3
Solution:
Let the two numbers be X and Y.
Then, Y - (30/100)X = (4/5)Y
Y/5 = (3/10)X
X : Y = 2 : 3
Question - 18.
The ratio of car speeds of a, car, train and bus is 5 : 9 : 4. The average speed of car, the bus and the train is 72km/hr together. What is the average speed of the car and train together?
82 km/hr
74 km/hr
84 km/hr
80 km/hr
Solution:
Average speed = 72 km/hr
(5X + 9X + 4X)/3 = 72 km/hr
6X = 72
X = 12
Average speed of Car and train = (5X + 9X)/2
Average speed of Car and train = 7X = 7 x 12 = 84 km/hr
Question - 19.
In the following number series only one is wrong. Find out the wrong number ?
32 33 37 41 62 87
33
37
41
62
Solution:
41 is wrong.
Addition of square
32 + 1 = 33
33 + 4 = 37
37 + 9 = 46
Question - 20.
1. X² - X - 12 = 0
2. Y² + 5Y + 6 = 0
X > Y
X < Y
X ≤ Y
X ≥ Y
Solution:
X² - X - 12 = 0
X² -4X + 3X - 12 = 0
X(X - 4) + 3(X - 4) = 0
(X - 4)(X + 3) = 0
X = 4, -3
Y² + 5Y + 6 = 0
Y² + 3Y + 2Y + 6 = 0
Y(Y + 3) + 2(Y + 3) = 0
(Y + 3)(Y + 2) = 0
Y = -3 , -2
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